Finding the percentage (Python 3)
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# Finding the percentage (Python 3)

• The provided code stub will read in a dictionary containing key/value pairs of name:[marks] for a list of students. Print the average of the marks array for the student name provided, showing 2 places after the decimal.

• Example
• marks key : value pairs are
• ‘alpha’ : [20, 30, 40]
• ‘beta’ : [30, 50, 70]
• query_name : ‘beta’
• The query_name is ‘beta’. beta’s average score is (30 + 50 + 70) / 3 = 50.0.

• Input Format
• The first line contains the integer n, the number of students’ records. The next n lines contain the names and marks obtained by a student, each value separated by a space. The final line contains query_name, the name of a student to query.
• Constraints
• 2 <= n <= 10
• 0 <= marks[i] <= 100
• lenth of marks array = 3
• Output Format
• Print one line: The average of the marks obtained by the particular student correct to 2 decimal places.

#### 문제풀이

• 이름과 숫자가 주어지고, 마지막에 입력된 이름에 대해 숫자에 대한 평균을 구하는것
• sum과 len 함수를 이용하여 평균을 구하였다.
```1 2 3 4 5 6 7 8 9 if __name__ == '__main__': n = int(input()) student_marks = {} for _ in range(n): name, *line = input().split() scores = list(map(float, line)) student_marks[name] = scores query_name = input() print('%0.2f' % (sum(student_marks[query_name])/len(student_marks[query_name]))) ```
```1 2 3 4 5 6 7 2 Harsh 25 26.5 28 Anurag 26 28 30 Harsh 26.50 ```