Compare the Triplets (Python 3)
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# Compare the Triplets (Python 3)

• Alice and Bob each created one problem for HackerRank. A reviewer rates the two challenges, awarding points on a scale from 1 to 100 for three categories: problem clarity, originality, and difficulty.
• The rating for Alice’s challenge is the triplet a = (a, a, a), and the rating for Bob’s challenge is the triplet b = (b, b, b).

• The task is to find their comparison points by comparing a with b, a with b, and a with b.
• If a[i] > b[i], then Alice is awarded 1 point.
• If a[i] < b[i], then Bob is awarded 1 point.
• If a[i] = b[i], then neither person receives a point.
• Comparison points is the total points a person earned.
• Given a and b, determine their respective comparison points.

• Example
• a = [1, 2, 3]
• b = [3, 2, 1]

• For elements 0, Bob is awarded a point because a .
• For the equal elements a and b, no points are earned.
• Finally, for elements 2, a > b so Alice receives a point.
• The return array is [1, 1] with Alice’s score first and Bob’s second.

• Function Description
• Complete the function compareTriplets in the editor below.
• compareTriplets has the following parameter(s):
• int a: Alice’s challenge rating
• int b: Bob’s challenge rating
• Return
• int: Alice’s score is in the first position, and Bob’s score is in the second.
• Input Format
• The first line contains 3 space-separated integers, a, a, and a, the respective values in triplet a.
• The second line contains 3 space-separated integers, b, b, and b, the respective values in triplet b.
• Constraints
• 1 ≤ a[i] ≤ 100
• 1 ≤ b[i] ≤ 100

#### 문제풀이

• a,b의 배열의 원소의 크기를 확인후, 더 큰쪽에 점수를 +1씩 하는 함수를 작성
• 배열의 index를 for문으로 돌려서 if문으로 더 큰쪽에 +1를 하는 코드를 작성 후 해당 점수들을 return하는 함수를 작성하였다.
```1 2 3 4 5 6 7 8 9 def compareTriplets(a, b): alice = 0 bob = 0 for i in range(len(a)): if a[i] > b[i]: alice += 1 elif a[i] < b[i]: bob += 1 return alice, bob ```
```1 compareTriplets([1,2,3],[3,2,1]) ```
```1 (1, 1) ```